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ѧÉú±íSpeople£º
id name  

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Kid kename

Ñ¡¿Î±íCk£º
bid Cid£¨¿Î³Ìid£© Sid£¨Ñ§Éúid£©

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SQL code:
select m.* , n.* from speople m , ck n where m.id = n.sid and m.di not in
(select Sid from ck group by sid having count(1) = (select count(1) from kech))
order by m.id , n.cid


SQL code:
--try
select kename
from kech
group by kename
having count(distinct kename)=(select count(*)from Ck)



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