access与SqlServer 之时间与日期及其它SQL语句比较
1、Datediff:
1.1算出日期差:
1.access: datediff('d',fixdate,getdate())
2.sqlserver: datediff(day,fixdate,getdate())
ACCESS实例: select * from table where data=datediff('d',fixdate,getdate())
sqlserver实例: select * from table where data=datediff(day,fixdate,getdate())
1.2算出时间差:
1.access: datediff('h',fixdate,getdate())
2.sqlserver: datediff(Hour,'2004-12-10',getdate())
ACCESS实例: select DATEDIFF('h',HMD,getdate())
sqlserver实例: select datediff(Hour,'2004-12-10',getdate())
1.3算出月份差:
1.access: datediff('m',fixdate,getdate())
2.sqlserver: datediff(Month,'2004-12-10',getdate())
ACCESS实例: select DATEDIFF('m',HMD,getdate())
sqlserver实例: select datediff(Month,'2004-12-10',getdate())
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2、日期变量
1.access: #"&data&"#
2.sqlserver: '"&data&"'
ACCESS实例: select * from table where data=#"&data&"#
sqlserver实例: select * from table where data='"&data&"'
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3、是否
1.access: not finished
2.sqlserver: finished=0
ACCESS实例: select * from table where not finished
sqlserver实例: select * from table where finished=0
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4、求余数
1.access: a mod b=100
2.sqlserver: a % b =100
ACCESS实例: select a mod b=100 from table where not finished
sqlserver实例: select a % b =100 from table where finished=0
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不知道这样的要求能不能实现?
比如我有一张表T1,里面只有一个字段1
里面有100条记录,如下所示:
字段1
A1
A2
A3
A4
...
A100
我想用一条SQL显示这样的结果
第一列 第二列 ... 第十列
A1 A11 &nb ......
项目中需要根据课件名称按月统计出访问的情况,第一次我采用了最土的一种办法,使用循环,给sql传递年月两个参数,
for(var y=2009;y<=2010;y++){
for(var m=1;m<=12;m++){
// todo : SQL 查询
}
}
这样,统计2 ......
Select CONVERT(varchar(100), GETDATE(), 0): 05 16 2006 10:57AM
Select CONVERT(varchar(100), GETDATE(), 1): 05/16/06
Select CONVERT(varchar(100), GETDATE(), 2): 06.05.16
Select CONVERT(varchar(100), GETDATE(), 3): 16/05/06
Select CONVERT(varchar(100), GETDATE(), 4): 16.05.06
Select CONVERT(varch ......
---SQL实现完全排列组合
create function F_strSpit(@s varchar(200)) returns table
as
return(
select value=substring(@s,i,num)+substring(@s,num-1+j,1)
from (select num=number from spt_values where type='p' and number<len(@s) and number>0)TA,
(select i=number+1 from spt_values where type='p ......