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from (
select u.user_id,u.login_name,e.* from cphrms.EXAM_USER eu, cphrms.users u, cphrms.exam_info e
where eu.user_id = u.user_id and eu.exam_id = e.exam_id
) ks
left join
(select t.exam_id, t.user_id, sum(t.score) as score from cphrms.user_answer t group by t.exam_id, t.user_id) cj
on
ks.user_id = cj.user_id and ks.exam_id=cj.exam_id
where ks.login_name = '19901'
order by start_time
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