javascript parseInt is broken
javascript parseInt is broken
I was debugging some strange errors in a date conversion function I was writing, and I stumbled upon something that amazed me... a strange bug in parseInt
>>>parseInt('06')
6
>>>parseInt('07')
7
>>>parseInt('08')
0
>>>parseInt('09')
0
>>>parseFloat('08')
8
>>>parseFloat('09')
9
Clearly for the strings '08' and '09' parseInt fails to return the right value. One workaround is easy, use parseFloat.
Why does this happen and where should I report this? I find it extremely odd that it happens in both Firefox and Internet Explorer 6 & 7; there must be some explanation right?
You can test it out for yourself using the FireBug javascript console), or by using one of these two links
alert(parseInt('07')+' == 7 ?')
alert(parseInt('08')+' == 8 ?')
Ok, Ok, so now that I explained how you would expect it to work (and clearly how I expected it to work) I'm going to answer my own question (yes I hate it when I do that too)
The problem is with how parseInt guesses the base of your number. Read the parseInt spec. Instead of always defaulting to base 10, it tries to guess, and if the first character is '0' it thinks you want to parse as an octal number, and if it starts with '0x' it thinks you want hexadecimal.
So, the solution is either to use parseFloat or to always specify your base.
Defaults that change on their own can't be trusted.
>>>parseInt('08',10)
8
相关文档：
1、插入排序->直接插入法排序
function InsertSort(arr) { //插入排序->直接插入法排序
var st = new Date();
var temp, j;
for(var i=1; i<arr.length; i++) {
if((arr[i]) < (arr[i-1])) {
temp = arr[i];
j = i-1;
do {
arr[j+1] = arr[j];
j--;
}
whil ......
flex 和javascript互相调用。
一、flex 调用javascript
只需使用静态的ExternalInterface.call就可以了。
call 方法至少要求一个参数，就所调用额函数的名称。
也可以传递参数。
如：
ExternalInterface.call("alert","hello");
"hello"就是作为alert� ......
以下全是个人理解以及网上查找而来,如有不对请指正...
假如有n段js代码 用<script>标签隔开的.
运行顺序是
step1. 读入第一个代码段
step2. 做语法分析，有错则报语法错误（比如括号不匹配等），并跳转到step5
step3. 对var变量和function定义做“预解析”（永远不会报错的，因为只解析正确的声明）
......
JavaScript过滤数组中重复元素
我是个JS初学者，我即将要说的这个方法也是大部分人都能想到的：
从旧数组中取元素，一个个添加到新数组中，在添加的时候，与添加过的元素比较，如果相同，则不添加。
首先定义两个数组：
Code
var arrA = new Array(1,23,43,64,1,23,5,8,3,5,9);
var arrB&n ......
<html>
<body>
<SCRIPT type="text/javascript">
<!--
var target=[]
var time_id=[]
function ShowDateTime(){
setTimeout("ShowDateTime()", 1000);
for (var i=0,j=target.length;i<j;i++)
{
var today=new Date();
timeo ......
