脚本1:
SELECT NAME
,value
,description
from ( --GV$SYSTEM_PARAMETER
SELECT x.inst_id as instance
,x.indx+1
,ksppinm as NAME
,ksppity
,ksppstvl as value
,ksppstdf as isdefault
,decode(bitand(ksppiflg/256,1),1,'TRUE','FALSE') as ISEM
,decode(bitand(ksppiflg/65536,3),
1,'IMMEDIATE',2,'DEFERRED','FALSE') as ISYM
,decode(bitand(ksppstvf,7),1,'MODIFIED','FALSE') as IMOD
,decode(bitand(ksppstvf,2),2,'TRUE','FALSE') as IADJ
,ksppdesc as DESCRIPTION
from x$ksppi x
,x$ksppsv y
WHERE x.indx = y.indx
AND substr(ksppinm,1,1) = '_'
AND x.inst_id = USERENV('Instance')
)
ORDER BY NAME;
http://space.itpub.net/14241337/viewspace-442363
脚本2:
SELECT
a.ksppinm "Parameter",
b.ksppstvl "Session Value",
c.ksppstvl "Instance Value"
from
x$ksppi a,
x$ksppcv b,
x$ksppsv c
WHERE
a.indx = b.indx
AND
a.indx = c.indx
AND
a.ksppinm LIKE '/_%' escape '/'
/
经常用oracle的人对下面的这条信息肯定不会陌生:“监听程序当前无法识别链接描述符中请求的服务”。其实产生这个问题的根本原因不是监听没有起来,而是监听没有监听你要连接的oracle实例。
大家都明白,oracle只有两者兼备才能向外界提供服务:一个是监听,用于接 ......