ORACLE对字母和数字混合的数据排序
主要是通过replace和translate来实现
SQL> create view v_tt
2 as
3 select ename||' '||deptno as data
4 from emp;
View created.
SQL> select * from v_tt;
DATA
---------------------------------------------------
SMITH 20
ALLEN 30
WARD 30
JONES 20
MARTIN 30
BLAKE 30
CLARK 10
SCOTT 20
KING 10
TURNER 30
ADAMS 20
DATA
---------------------------------------------------
JAMES 30
FORD 20
MILLER 10
14 rows selected.
//by deptno
SQL> select * from v_tt
2 order by replace(data,replace(translate(data,'0123456789','##########'),'#'
,''),'');
DATA
---------------------------------------------------
CLARK 10
KING 10
MILLER 10
JONES 20
FORD 20
ADAMS 20
SMITH 20
SCOTT 20
WARD 30
TURNER 30
ALLEN 30
DATA
---------------------------------------------------
JAMES 30
BLAKE 30
MARTIN 30
14 rows selected.
//by name
SQL> select * from v_tt
2 order by data,replace(translate(data,'0123456789','##########'),'#','');
DATA
---------------------------------------------------
ADAMS 20
ALLEN 30
BLAKE 30
CLARK 10
FORD 20
JAMES 30
JONES 20
KING 10
MARTIN 30
MILLER 10
SCOTT 20
DATA
---------------------------------------------------
SMITH 20
TURNER 30
WARD 30
14 rows selected.
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虽然学习Java很久了，自己也连接过一些数据库，比如mysql之类的，如今呢，也学习了一段时间的Oracle，然而呢，今天是我第一次连接Oracle，嘿嘿，应该还不算太迟吧。
今天呢，有点笨拙，大家莫笑！
我这是一个查询例子
首先，� ......
select t.lot_number
from inv.mtl_onhand_quantities_detail t
left join mtl_system_items_b mi
on t.inventory_item_id = mi.inventory_item_id
where mi.segment1 like '101%' and mi.organization_id = 102
group by t.lot_number having count(*)=1 union
select t.lot_number||'x'
......
最简单的是使用
/* Formatted on 2009/12/02 16:01 (Formatter Plus v4.8.8) */
SELECT TO_CHAR (TO_DATE ('2009-12-02', 'YYYY-MM-DD'), 'WW')
from DUAL;
不过to_char()函数在计算一年中第几周是从该年的1月1日开始的。
以下SQL 能得到正确的自然周数.
/* Formatted ......
http://www.cnblogs.com/ajian/archive/2009/08/25/1421063.html
TO_DATE格式(以时间:2007-11-02 13:45:25为例)
Year:
yy two digits 两位年 &nbs ......
