1.初始化实验坏境
1）创建测试表group_test
sec@ora10g> create table group_test (group_id int, job varchar2(10), name varchar2(10), salary int);
Table created.
2）初始化数据
insert into group_test values (10,'Coding', 'Bruce',1000);
insert into group_test values (10,'Programmer','Clair',1000);
insert into group_test values (10,'Architect', 'Gideon',1000);
insert into group_test values (10,'Director', 'Hill',1000);
insert into group_test values (20,'Coding', 'Jason',2000);
insert into group_test values (20,'Programmer','Joey',2000);
insert into group_test values (20,'Architect', 'Martin',2000);
insert into group_test values (20,'Director', 'Michael',2000);
insert into group_test values (30,'Coding', 'Rebecca',3000);
insert into group_test values (30,'Programmer','Rex',3000);
insert into group_test values (30,'Architect', 'Richard',3000);
insert into group_test values (30,'Director', 'Sabrina',3000);
insert into group_test values (40,'Coding', 'Samuel',4000);
insert into group_test values (40,'Programmer','Susy',4000);
insert into group_test values (40,'Architect', 'Tina',4000);
insert into group_test values (40,'Director', 'Wendy',4000);
commit;
3）初始化之后的数据情况如下：
sec@ora10g> select * from group_test;
GROUP_ID JOB NAME SALARY
---------- ---------- ---------- ----------
10 Coding Bruce 1000
10 Programmer Clair 1000
10 Architect Gideon 1000
虽然学习Java很久了，自己也连接过一些数据库，比如mysql之类的，如今呢，也学习了一段时间的Oracle，然而呢，今天是我第一次连接Oracle，嘿嘿，应该还不算太迟吧。
今天呢，有点笨拙，大家莫笑！
我这是一个查询例子
首先，� ......
select r.rollid as rollid from zh1_rool r where r.date_p >=to_date('2009-11-26 23:59:59','yyyy-mm-dd hh24:mi:ss') and rollid not in
(select t.lot_number as rollid
from inv.mtl_onhand_quantities_detail t
left join mtl_system_items_b mi
on t.inventory_item_id = mi.inventory_ ......
