1.
SQL> desc gjh_a05 ;
Name Type Nullable Default Comments
----- ------------- -------- ------- --------
A0500 VARCHAR2(2) Y
A0501 VARCHAR2(6)
A0502 VARCHAR2(10) Y
A0503 VARCHAR2(10) Y
A0504 VARCHAR2(20) Y &nb ......
/*
* Source URL: http://jonsion.javaeye.com/blog/511584
*/
1. 获取所有数据库名
1> SELECT name from master..sysdatabases;
2> go
2. 获取所有表名
1> USE master
2> go
1> SELECT name from sysobjects WHERE type='U';
2> go
3. 获取所有字段名
1> SELECT name from syscolumns WHERE id=object_id('table_name');
......
对这个进行优化
select n5001 门店,n5002 部门,n5004 小分类,n5019 商品编码,c01d21 商品名称,
nvl(xse,0)-nvl(dzxs,0) 销售,
mle 毛利,
nvl(xl,0)-nvl(dzsl,0) 销量
from
(select n5001,n5002,n5004,n5019,sum(n5011) xse,sum(n5016) mle,sum(n5023) xl
from n50
where to_char(n5010,'yyyymmdd')>='20100401'
and to_char(n5010,'yyyymmdd')<='20100431'
group by n5001,n5002,n5004,n5019),
(select g08,g09,g02,sum(g03*g07) dzxs,sum(G03) dzsl from batchgoods
where to_char(g04,'yyyymmdd')>='20100401'
and to_char(g04,'yyyymmdd')<='20100431'
group by g08,g09,g02),c01d
where n5001=g08(+)
and n5019=g02(+)
and n5001=c01d00(+)
and n5019=c01d01(+)
执行计划
SELECT STATEMENT, GOAL = CHOOSE Cost=10060 Cardinality=3931 Bytes=475651
MERGE JOIN OUTER Cost=10060 Cardinality=3931 Bytes=475651
SO ......
select top PageSize * from 表
where 条件 and id not in
(select top PageSize*(CurrentPageIndex-1) id from 表 where 条件 order by 排序条件)
order by 排序条件
《PageSize 是GridView中每页显示的信息条数,PageSize*(CurrentPageIndex-1) 在SQL中不识别,需定义变量来替换》 ......
上集中
//////////////////////////////////////////////////
select n5001 门店,n5002 部门,n5004 小分类,n5019 商品编码,c01d21 商品名称,
nvl(xse,0)-nvl(dzxs,0) 销售,
mle 毛利,
nvl(xl,0)-nvl(dzsl,0) 销量
from
(select n5001,n5002,n5004,n5019,sum(n5011) xse,sum(n5016) mle,sum(n5023) xl
from n50
where n5010 between to_date('20100401','yyyymmdd') and to_date('20100430','yyyymmdd')
group by n5001,n5002,n5004,n5019),
(select g08,g09,g02,sum(g03*g07) dzxs,sum(G03) dzsl from batchgoods
where g04 between to_date('20100401','yyyymmdd') and to_date('20100430','yyyymmdd')
group by g08,g09,g02),c01d
where n5001=g08(+)
and n5019=g02(+)
and n5001=c01d00(+)
and n5019=c01d01(+)
SELECT STATEMENT, GOAL = CHOOSE Cost=10163 Cardinality=30832 Bytes=3730672
MERGE JOIN OUTER Cost=10163 Cardinality=30832   ......
在程序中我们可能经常会遇到这种情况,比如要取一个listbox里面的选择项,得到的结果可能是string ID="id1,id2,id3,id4",然后我们要把这些ID插入到数据库中,同时每个id对应的是要插入一条记录。实现的方法有很多,但是如果我们通过下面这个函数(RecurrentSplit)就能简单的达到上述效果。RecurrentSplit的使用也非常简单。
例如:
select row_number()over(order by indexno desc) as seq ,* from recurrentsplit('1,2,3,4,5,',',',0,0)
这样我们就会分成5条记录,因为我的要求是一个listbox中item[i]其中最小的说明他的排序在最前头,同时排序是但SEQ的降序排列。所以在这个查询中我用row_number()over(order by indexno desc) as seq得出了他的顺序号
如下
seq indexno SplitName
1 4 5
2 3 4
3 2 3
4  ......