<?xml version="1.0" encoding="UTF-8" ?>
<list version="3.0">
<title>title</title>
<book>
<type>
<id>1022</msgid>
<name>66</name>
</type>
......
<type>
<id>1023</id>
<name>77</name>
</type>
</book>
</list>
读取：
Set XML = Server.CreateObject ("Microsoft.XMLDOM")
xml.async = False
xml.Load Request
set root=xml.documentElement
title= root.childNodes.item(0).text
Set oXMLItems = root.selectNodes("book")
oXMLtype=oXMLItems(0).selectNodes("type")
iLength = oXMLtype.length - 1
For i = 0 To iLength
Set oXMLItem = oXMLmessages.item(i)
id= oXMLItem.getAttribute("id")
name= oXMLItem.getAttribute("name")
Next
高手指点错在哪啊。。。
<?xml version="1.0" encoding="UTF-8" ?>
<list version="3.0">
<title>title</title>
<book>
<type>
<id>1022</msgid>
<name>66</name>
<UserModel xmlns="http://tempuri.org/">
<Name>Liu</Name>
<Age>23</Age>
</UserModel>
怎么用linq to xml 查询把上面的一个字符串 投影成一� ......
