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select userid,count(userid) from ¼Ç¼Áбí group by useridÒýÓà select a.UserId as UserId,b.i as i from Óû§Áбí as a inner join (select UserId,count(day) as i from ¼Ç¼Áбí) as b on a.UserId=b.UserId order by a.UserId ºÃÏñ²»ÐÐÄØ Ò»¸öÊÇÓû§Áбí ID 1 2 3 4 Ò»¸öÊǼǼÁбí(ÿ¸öÓû§Ò»Ìì¿ÉÄÜÓжàÌõÊý¾Ý) UserID Day 1 2009-09-22 1 2009-09-22 1 2009-09-22 1 2009-09-23 2 2009-09-22 2 2009-09-22 2 2009-09-22 2 2009-09-22 4 2009-09-22 4 2009-09-22 ÏëÒªµÄ½á¹ûÊÇ µ±Ììÿ¸öÓû§µÄ×ÜÊý 1 3 2 4 4 2 select d.id,count(*) as ÊýÁ¿ from (SELECT a.id ,b.day from a inner join b on a.UserId =b.UserId ) d order by d.id SQL code Code highlighting produced by Actip
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