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id name id money
1 ÕÅÈý 1 1000
2 ÀîËÄ 2 5000
3 ÕÅÈý 3 3000
4 ÀîËÄ 4 7000

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1£©  
name money  
ÕÅÈý 4000  
ÀîËÄ 12000

2£© £¨×¢£º×îºÃ²»ÓÃwhere name='ÀîËÄ'ÕâÀàµÄ£¬ÒòΪ¿ÉÄÜÈËÃû²»Êǹ̶¨µÄ£©
ÕÅÈý ÀîËÄ
4000 12000

1µÄ
select a.name as,sum(money) 
from a,b
where a.id=b.id
group by a.name
order by a.name;

SQL code:
--1.
select a.name,sum(b.[money]) [money] from ta a join tb b on a.id=b.id group by a.name


ÓÐ×ö³ö2µÄÂð£¿

SQL code:
--2.


/*------------------------------------------------------------------
-- Author : htl258(Tony)
-- Date : 2010-04-15 21:06:16
-- Version: Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86)
Jul 9 2008 14:43:34
Copyright (c) 1988-2008 Microsoft Corporation
Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3)

------------------------------------------------------------------*/
--&g


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