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id name id money
1 ÕÅÈý 1 1000
2 ÀîËÄ 2 5000
3 ÕÅÈý 3 3000
4 ÀîËÄ 4 7000
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name money
ÕÅÈý 4000
ÀîËÄ 12000
2£© £¨×¢£º×îºÃ²»ÓÃwhere name='ÀîËÄ'ÕâÀàµÄ£¬ÒòΪ¿ÉÄÜÈËÃû²»Êǹ̶¨µÄ£©
ÕÅÈý ÀîËÄ
4000 12000
1µÄ
select a.name as,sum(money)
from a,b
where a.id=b.id
group by a.name
order by a.name;
SQL code:
--1.
select a.name,sum(b.[money]) [money] from ta a join tb b on a.id=b.id group by a.name
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SQL code:
--2.
/*------------------------------------------------------------------
-- Author : htl258(Tony)
-- Date : 2010-04-15 21:06:16
-- Version: Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86)
Jul 9 2008 14:43:34
Copyright (c) 1988-2008 Microsoft Corporation
Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3)
------------------------------------------------------------------*/
--&g
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from ht left join gfdm on ht.gfdm=gfdm.gfdm
join jh on ht.htbh=jh.hth
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XML code:
<upd:Update xmlns:lar="http://schemas.microsoft.com/msus/2002/12/LogicalApplicabilityRules" xmlns:cmd="http://schemas.microsoft.com/msus/2002/12/Up ......