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select a.dname as '²¿ÃűàºÅ' , max(c.salary) as 'ƽ¾ù¹¤×Ê' from depa as a inner join emp as b on a.dno=b.dno inner join salary as c on b.eno=c.eno group by a.dname order by 'ƽ¾ù¹¤×Ê' desc
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select Ô±¹¤ÐÕÃû=emp.name,+Äã×Ô¼ºÐ´µÄÄÇÒ»´®¾Í¿ÉÒÔÁË
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ÊDz»ÊÇÔ±¹¤±íÀïÄãÉÙЩÁËÒ»ÁУ¬Óиöename?
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SQL code:
select d.dname,d.¹¤×Ê as ×î¸ß¹¤×Ê,b.eno,b.ename from (select a.dname,max (c.salary) ¹¤×Ê
from a,b,c
where a.dno=b.dno and b.eno=c.eno
group by a.dname ) d,b,c
where d.¹¤×Ê=c.salary and c.eno=b.eno
order by d.¹¤×Ê desc
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select convert(varchar(50),cast(convert(numeric(18,2),1275674000000/100000000)as real))+'ÒÚ'
select cast(convert(numeric(18,2),1275674000000/100000000)as real)
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date(Ö÷) outid(Ö÷) inid(Ö÷) num amt
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select ²¿ÃÅ,ÐÕÃû from tb
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XML code:
<folder state="unchecked" label="È«²¿">
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select ht.gfdm,gfdm.gfmc,gfdm.lb ,sum(jh.htdj*jh.htsl)as je
from ht left join gfdm on ht.gfdm=gfdm.gfdm
join jh on ht.htbh=jh.hth
and ht.htbh not like'del%' and ht. ......