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ÎÒÏÖÔÚÓиöComments×ֶΣ¬Êý¾ÝÀàÐÍÊÇnvarchar(500)ÎÒÏëÒªµÄЧ¹û¾ÍÊÇÖ»ÒªComments×ֶΰüº¬ÎҵĴÊÓï¾Í²éѯ³öÀ´£¬ÈçÏ£º
select * from table WHERE CONTAINS(Comments,'"ºìÂ¥ÃÎ"')
µ«ÊÇÎÒÏÖÔÚÓÐÈô¸É¸ö´ÊÓ±ÈÈ磺 ºìÂ¥ÃÎ,Ò»Á±ÓÄÃÎ,ºûµû·É·É,Óêµû,ˮ䰴«,Î÷ÓμÇ,Èý¹úÑÝÒå,Ц°Á½­ºþ µÈµÈ
ÎÒÒªµÄ½á¹ûÊÇÖ»ÒªComments×ֶΰüº¬ÎÒµÄÈô¸É¸ö´ÊÓï3¸öÒÔÉϾÍÒª£¬ÎÒÊÔÁËÓÃsqlʵÏÖ²»ÁË£¬¹À¼ÆÒªÓô洢¹ý³ÌÈ¥´¦Àí£¬Çë´ó¼Ò°ïæдÏ¡£Ð»Ð»£¡(²éѯÊý¾ÝÓÐ20Íò×óÓÒ£¬ÒªÇóЧÂÊÖ´Ðиß) 
SQL code:
declare @s varchar(1000),@sql varchar(8000)
set @s='ºìÂ¥ÃÎ,Ò»Á±ÓÄÃÎ,ºûµû·É·É,Óêµû,ˮ䰴«,Î÷ÓμÇ,Èý¹úÑÝÒå,Ц°Á½­ºþ'
set @s='select '''+replace(@s,',',''' as col union all select ''')+''''

set @sql='select a.Comments
from [table] a,
(select * from ('+@s+') t ) b
WHERE charindex(b.col,a.Comments)>0
group by a.Comments
having count(1)>=3'

--print @sql

exec (@sql)


Èç¹û»¹ÒªÏÔʾÆäËû×ֶΣ¬ÔÚset @sql='select a.Comments ºóÃæ¼Ó£¬²¢¼Óµ½group byºóÃæ

1Â¥µÄ·½·¨¿ÉÒÔʵÏÖ£¬µ«ÊÇÓиöÎÊÌ⣬ЧÂʺܵͣ¬ÎÒÔÚ20ÍòÊý¾ÝÖвéѯtop 1000 ¶¼Òª 3 Ãë
Äܲ»ÄÜ°Ñ select 'ºìÂ¥ÃÎ' as col ÕâÑùµÄ×éºÏ·½Ê½¸Ä³ÉЧÂʸߵġ£Ð»Ð»£¡½â¾öÁ¢¿Ì½áÌù£¡


select a.Comments
from [table] a,dbo.fn_split(@s,',') b
WHERE charindex(b.col,a.Comments)>0
group by a.Comments
having count(1)>=3

ÕâÀïµÄ b.col ²»¶Ô°É£¬Õâ¸öº¯ÊýÖÐÃ


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