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001 a
002 b
003 c
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001 11 2009-01-13
001 2 2009-02-26
002 3 2009-01-13
002 1 2009-02-26
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Óû§±àÂë Óû§Ãû³Æ ±¾ÆÚÖ¸Êý
001 a 2
002 b 1
003 c 0
SQL code:
SELECT A.Óû§±àÂë,Óû§Ãû³Æ, ±¾ÆÚÖ¸Êý =COUNT(*)
from YH A,YS B
WHERE A.Óû§±àÂë=B.Óû§±àÂë
GROUP BY A.Óû§±àÂë,Óû§Ãû³Æ
SQL code:
select
yh.*,
isnull(ys.±¾ÆÚÖ¸Êý,0) as ±¾ÆÚÖ¸Êý
from
yh
left join
ys
on yh.Óû§±àÂë =ys.Óû§±àÂë
and not exists(select 1 from ys t where t.Óû§±àÂë=ys.Óû§±àÂë and t.³±íʱ¼ä>ys.³±íʱ¼ä)
select c.*,t.³±íʱ¼ä
from yb c,(
select *
from ys a
where not exists (select 1
from ys b
where a.Óû§±àÂë=b.Óû§±àÂë and a.³¬±êʱ¼ä<b.³±íʱ
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a1
id name aa cc
001 aaaa bbb cc
002 bbb bbb bbb
003 ccc ccc ccc
004 ddd ddd ddd
005 eee eee eee
a2
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columnA
'222'
'33%44'
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лл
select * from a
where columna like '%/%%' escape '/'
UP
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