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name ¹«Ë¾Ãû count ÈËÊý

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select name, count(name)  from  ±í group by name

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select name, count(name)  from  ±í group by name

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SELECT A.¹«Ë¾Ãû³Æ£¬ B.ÈËÊý
from ¹«Ë¾±í A
JOIN (SELECT ¹«Ë¾ID, COUNT(1) AS ÈËÊý from Ô±¹¤±í GROUP BY ¹«Ë¾ID) B
ON A.¹«Ë¾ID=B.¹«Ë¾ID


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SQL codeSELECT A.NAMEAS ¹«Ë¾Ãû,COUNT(1)AS ÈËÊýfrom ¹«Ë¾±í A£¬ Ô±¹¤±í BWHERE A.¹«Ë¾ID= B.¹«Ë¾IDGROUPBY A.¹«Ë¾ID, A.¹«Ë¾Ãû

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SELECT A.NAME AS ¹«Ë¾Ãû, COUNT(1) AS ÈËÊý
  from ¹«Ë¾±í A£¬ Ô±¹¤±í B
WHERE A.¹«Ë¾ID = B.¹«Ë¾ID
GROUP BY A.¹«Ë¾ID, A.¹«Ë¾Ãû



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