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SQL code:
select a,count(*) from (
select a from tb where a=1
union all
select b from tb where b=1
union all
select d from tb where d=1
)t group by a


SQL code:
select 'a' as ×Ö¶ÎÃû,sum(case when a=1 then 1 else 0 end) as ¼Ç¼Êý from tb
union all
select 'b' as ×Ö¶ÎÃû,sum(case when b=1 then 1 else 0 end) as ¼Ç¼Êý from tb
union all
select 'd' as ×Ö¶ÎÃû,sum(case when d=1 then 1 else 0 end) as ¼Ç¼Êý from tb


select col,count(1) as ¼Ç¼Êý from tb group by col

SQL code:
select a as 'ÁÐÃû','¸öÊý'=(select count(a) from table where a=1)
union all
select b as 'ÁÐÃû','¸öÊý'=(select count(b) from table where b=1)
union all
select das 'ÁÐÃû' ,'¸öÊý'=(select count(d) from table where d=1)


select ×Ö¶Î='a',(select cout(1) from table where a=1)
union all
select 'b',(select cout(1) from table where b=1)
union all
select 'c',(select cout(1) from table where c=1)

SQL code
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