$sql = 'select tid from table_name'; 等待。。。。。。答案 这个是查表中tid字段里的值、现在是要找哪一张表中有tid字段。。。。。呵呵,不一样啊 SQL code: SELECT TABLE_SCHEMA AS `database`,TABLE_NAME AS `table` from information_schema.COLUMNS WHERE COLUMN_NAME='tid'
use information_schema; select TABLE_NAME from COLUMNS where COLUMN_NAME = 'tid'; 谢谢 foolbirdflyfirst,也谢谢coolesting,虽然用你的运行不出来结果。
CREATE DATABASE ADDRESSLIST; USE ADDRESSLIST; DROP TABLE IF EXISTS FRIEND; CREATE TABLE FRIEND (FRIEND_ID INTEGER NOT NULL AUTO_INCREMENT PRIMARY KEY , FRIEND_NAME VARCHAR(20) NOT N ......