Java code:
<td align="center" class="brightcyan-tb"><div align="left"><s:property value="name"/></div></td>
<td align="center" class="brightcyan-tb"><div align="left"><s:property value="sex"/></div></td>
<td align="center" class="brightcyan-tb"><div align="left"><s:date name="hireDate" format="yyyy-MM-dd"/></div></td>
<td align="center" class="brightcyan-tb"><div align="left"><s:property value="position"/></div></td>
<td align="center" class="brightcyan-tb"><div align="left"><s:a href="employee_showInfo.action?name=${name}" target="mainFrame">详细信息</s:a></div></td>
我想在链接中把获得的name传到action中
在action中有设置name 接收参数，可是启动项目的时候 就会提示出错
请各路大侠帮忙解决一下
错误是什么呢？？
CSS code:
前提是name中能取到值，你说启动时出错。可能是
org.apache.jasper.JasperException: Unable to compile class for JSP:
An error occurred at line: 52 in the jsp file: /vip_info.jsp
ÕË cannot be resolved
49: <table border="1& ......
