小弟刚学习jsp，写一程序出错大家帮帮忙 看看是哪里的错误啊 稍微解释下 谢谢啊
错误：
org.apache.jasper.JasperException: Before start of result set
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:510)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:375)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
javax.servlet.ServletException: Before start of result set
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:858)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:791)
org.apache.jsp.yanzheng_jsp._jspService(yanzheng_jsp.java:71)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:332)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
java.sql.SQLException: Before sta
新手:
tomcat+struts 2.0
jsp 页面直接关联model
现在需要根据model(admin)里面的一个item(id),判断jsp页面出现的内容.
大概流程:
...
<table>
<tr>
<td>
<s:if admin.id is null> ......
