将用ASCII编码的字符串用Java进行解码

如一个字符串是44414B4A3133363344313336335320676D4F33534C6675504C7544504456714264625852594B6343566961436E635547566146573069705A3079，是用ASCII编码的

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不太明白楼主的意思

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上面那个字符串是用ASCII编码的，现在我想将它进行解码，而且是要java语言写的程序

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Java code:

try {
String str = "44414B4A3133363344313336335320676D4F33534C6675504C7544504456714264625852594B6343566961436E635547566146";
System.out.println(new String(str.getBytes("ASCII"), "GBK"));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}


这个不知道符合要求不？

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Java code:

public static String unPack(String a) {
String un = new String("");
char[] cc = a.toCharArray();
for (int i = 0; i < (int)(cc.length/2); i++) {
un+= (char)(t2s(cc[i*2])*16+t2s(cc[i*2+1]));
}
return un;
}

public static int t2s(char a){
char[] s={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};

for (int i = 0; i < s.length; i++) {
if(a==s[i]){
return i;
}