SQL code:
select A.commandKey,A.enabled,A.commandFile,A.targetControl,A.rightId,A.type,[B].[value] as commandType,A.state,[C].[value] as commandState,A.parent,A.commandText,A.commandTipText,A.icon,A.description
from t_commands as A
inner join t_parameters as B on [A].[type]=[B].[code]
inner join t_parameters as C on [A].[state]=[C].[code]
where B.id=3 and C.id=4
如上SQL，执行的时候就提示“语法错误（操作符丢失）在‘[A].[type]=[B].[code]
inner join t_parameters as C on [A].[state]=[C].[code] ’中”的提示，然后我发现如果把后面的join语句去掉不连接的话就能正常查询出数据，是不是Access不支持多个连接查询的？
select * from (select * from table1 t1 left join table2 t2 on t1.id=t2.id) t left join table3
t3 on t.id=t3.id
只有用LEFT JOIN+RIGHT JOIN
select A.commandKey,A.enabled,A.commandFile,A.targetControl,A.rightId,A.type,.[value] as commandType,A.state,[C].[value] as commandState,A.parent,A.commandText,A.commandTipText,A.icon,A.description
from (t_commands as A
inner join t_parameters as B on [A].[type]=[B].[code] )
inner join t_parameters as C on [A].[state]=[C].[code]
where B.id=3 and C.id=4
[b]加上（）
学习中~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~顶起！！！！！！！！！！！！！！！
高手都帮你回答了
我就告诉
