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1+(x^2/2!)+(x^3/3!)+¡­¡­¡­+(x^n/n!)


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C/C++ code:
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <string.h>

int jc(int n){
int sum=1;
while(n){
sum = sum*n;
n--;
}
return sum;
}

double func(int x,int n){
double sum = 1.0;
while(n > 1){
sum += pow(x,n)/jc(n);
n--;
}
return sum;
}

int main(int s,char **p){
double i = func(1,2);
printf("%lf\n",i);

return 0;
}

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C/C++ code:

#include "stdio.h"
void main()
{
int s,x,n,i;
double sum=1.0;
int t=2;
scanf("%d,%d",&x,&n);
s=x*x;
for(i=2;i<=n;i++)
{
sum+=s/t;
s*=x;
t*=i;
}
printf("%f",sum);

}

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C/C++ code:
sum+=(1.0*s)/t;

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C/C++ code

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