table1
number name
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512 ÉϺ£
513 ¹ãÖÝ
514 ÉîÛÚ
611 ³É¶¼
612 ÖØÇì
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number ....
511
512
512
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number name count
511 ±±¾© 1
512 ÉϺ£ 2
513 ¹ãÖÝ 0
514 ÉîÛÚ 0
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select t1.name,t1.number, sum(nvl(t2.number, 0)) count from t1, t2 where t1.number=t2.number(+) and t1.number not like '61%' group by t1.name,t1.number
select t1.name,t1.number, sum(nvl(t2.number, 0)) count from t1, t2 where t1.number=t2.number(+) and t1.number not like '61%' group by t1.name,t1.number
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SQL code:
select distinct t1.number,t1.name,count(t2.number) over(partition by t1.name)
from table1 t1,table2 t2
where t1.number = t2.number
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