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C/C++ code:
(a*b)/(c*d)
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£¨a*b£©/(c*d)
C/C++ code:
(a*b)/(c*d);
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((a*b)/(c*d))
DING
......
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#include <stdio.h>
int main(){
int g[10];
int a,b,c;
int sum(int a,int b,int c);
scanf("%d%d%d",a,b,c);
while(a != 0&c!= 0&b!= 0&)
sum(a,b,c);
int i;
for(i = o;i <= 10;i++)
printf("%d\n",g[i]);
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